Limiting Reagents 
Using Limiting Reagents Practice Problems

The following practice problems are designed to test your knowledge on theoretical yield. If you feel as though you are not prepared to answer these questions, click on the link above to go back to the lesson
Directions: Solve the following problems solving for the answers in grams. 
Click here for reference to a periodic table!
Please have a calculator handy!

1
 For the balanced equation shown below, if 40.2 grams of Fe were reacted with 9.81 grams of H2O, how many grams of H2 would be produced?
3Fe+4H2O=>Fe3O4+4H2 


2. For the balanced equation shown below, if 1.75 grams of P4 were reacted with 1.68 grams of O2, how many grams of P4O10 would be produced?
P4+5O2=>P4O10
 

3. For the balanced equation shown below, if 55.4 grams of C2H3F were reacted with 55.6 grams of O2, how many grams of H2O would be produced?2C2H3F+5O2=>4CO2+2H2O+2HF

4. For the balanced equation shown below, if 29.3grams of Ba were reacted with 4.98 moles of 02, how many grams of BaO would be produced?
2Ba+O2=> 2BaO

5. For the balanced equation shown below, if 42.1 grams of ZnS were reacted with 10.9 grams of O2, how many grams of SO2 would be produced?
 2ZnS+3O2=>2ZnO+2SO2


6. For the balanced equation shown below, if 36.8 grams of CBr4 were reacted with 4.56 grams of O2, how many grams of Br2 would be produced?  
CBr4+O2=>CO2+2Br2


7. For the balanced equation shown below, if 13.2 grams of Fe were reacted with 31.5 grams of Cl2, how many grams of FeCl3 would be produced?  
2Fe+3Cl2=>2FeCl3


8.  For the balanced equation shown below, if 41.4 grams of Al were reacted with 190 grams of Cr2O3, how many grams of Cr would be produced?  
2Al+Cr2O3=>Al2O3+2Cr  


9. For the balanced equation shown below, if 59.3 grams of CH2S were reacted with 80.6 grams of O2, how many grams of SO3 would be produced? 
CH2S+3O2=>CO2+H2O+SO3


10. For the balanced equation shown below, if 11.0 grams of CH3COF were reacted with 4.97 grams of H2O, how many grams of CH3COOH would be produced? 
CH3COF+H2O=>CH3COOH+HF 

Check you answer's here!